Does that wirenut have black going into it AND those three reds?
If so, then your diagram must be wrong.
It looks to me like the black feeds to the switch, then to the wirenut, then to the three fuses - which then feed out to the lights, etc.
So the switch kills power to the fuses.
In which case, the switch gets power from + not from - as in your diagram.
Which is fine, except for the wrong colors being used (and the horrible workmanship).
Wrong color is also happening at the solenoid, where one battery + is black, and the other red.
No, it's just the picture, the black wire disappears into the battery box behind the wire nut. fairly sure the diagram is right. and yeah, the black wire at the solenoid threw me off at first.
Thanks! most of this makes sense and i think it explains the problem i'm having - draining the starter without even knowing why.You don't need to test resistance at this stage - just voltage and/or continuity.
Your test 1 shows a problem.
If the ignition is turned off, then there should be NO voltage at the skinny wire where it meets the solenoid.
In the photo, it appears to be wired directly to the battery + terminal of the alternator.
That would be the same as wiring it straight to the + on the engine battery.
And that is WRONG.
Wired that way, the solenoid is engaged and tying the engine and house batteries into a bank FULL TIME. (And the solenoid is drawing a bit of power out of both batteries 24/7.)<*>
This is further indicated by test 2 (engine running).
The batteries are at 13.7v, but the skinny wire feeding the solenoid is getting power directly from the alternator at 14.3v.
<*>I think I see what's happening there - whoever did it, didn't understand how it works.
I think they thought it was like a diode isolator (the ones with the heat sink you can buy at the auto parts store).
With a diode type, you run the charging wire to the center terminal of the diode isolator, and then run one wire out to each battery.
Which looks like what they did on your truck.
BUT
Yours is a solenoid type called a "split-charge relay" and doesn't work the same way as a diode type at all.
The skinny wire activating the solenoid should normally be wired so that it only has power when the ignition switch is on.
Disconnect it from the alternator ASAP and hook it to an ignition circuit.
So this makes sense too... in theory. i'm just not sure how best to get in there to the alternator and also not sure where ignition circuits are... Doesn't sound like a hard thing to look up and figure out.